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The solution of differential equation $y''+3y'+2y=0$ is of the form

1. $C_1e^x+C_2e^{2x}$

2. $C_1e^{-x}+C_2e^{3x}$

3. $C_1e^{-x}+C_2e^{-2x}$

4. $C_1e^{-2x}+C_2e^{-x}$

ans is c.

here y''-(-3)y'+2y=0

therefore y=c1e^2x + c2e^x

and solving we get c1e^-x + c2e^-2x
by

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What is difference between option C and option D

1
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