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A class B network address 130.50.0.0 is submitted as follows. The last 10 bits of the host I'd are allotte for host number and the remaining 6 bits are reserved for subnet number.

Q- what are the first hosts address of 1st and 4th subnets?

1. 130.50.4.1 and 130.50.16.1
2. 130.50.1.1 and 130.50.4.1
3. 130.50.0.0 and 130.50.3.0
4. None of these
edited | 107 views
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130.50.0.0 .Last 16 bit can be written in binary as 00000000 00000000.

Now,we need first host of first subnet So, 00000100 00000001 which will be 130.50.4.1

First host of 4th subnet will be 00010000 00000001 which will be 130.50.16.1
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A same reason
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How did you go to the 4th subnet?
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First subnet means 000000

4th subnet means 000011

isn't it ? ( We have to start from 0 right ? I mean there is no word as zeroth subnet)
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Thanks got it
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@Shaik Masthan  @adarsh_1997 ..the first host of first subnet is 130.50.0.1 isin't it?

I got confused!

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Yes, as per me

It is 130.50.0.1 and 130.50.12.1
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yes same like for 4 subnet 2 bits are used (00,01,10,11) 00 represent first subnet and so on.

for 64 subnet 6 bits will be used in sid part(000000 for 1st subnet,000001 for 2nd subnet and for 4th subnet 000011)
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Yes, It will be  130.50.0.1 and 130.50.12.1.

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No,we don't count first as 0000 because it is used as subnet id.It is not host.Host always starts from 0001.

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Host always starts from 0001.

130.50.0.1 ---- isn't it starts with 1

it is actually lead to Option D. (  130.50.0.1 and 130.50.12.1 )

But it is a non-standard question, i mean the question is not well formed... no need of further discussion

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