drdo 2013

Question

let A(1:8, -5:5, -10:5) be a three dimentional arrey. how many elements are there in the arrey A

Comments

A(1:8, -5:5, -10:5)

1-8 => 8 element .... -5:5 => 11element and -10-5 => 16elements

then total elements are $8*11*16 = 1408 $

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same .. https://gateoverflow.in/43751/isro-2013-1

Answer 1

No of elements in 3d=No of elements in 1st dimension*No of elements in 2dimension*No of elements in 3rd dimension(by dimension I mean the index)

Number of elements in first dimension= upper limit - lower limit + 1 = 8 - 1 + 1 =8

Number of elements in second dimension of array = 5 - (-5) + 1 = 11

Number of elements in third dimension of array = 15 - (-10) + 1 = 16

Hence, total number of elements = 8 * 11 * 16 = 1408