0 votes 0 votes My doubt is in second hasse diagram for (I,g) lub should be I and j so it is not lattice please correct me if i amwrong Set Theory & Algebra zeal discrete-mathematics set-theory&algebra lattice + – Prince Sindhiya asked Nov 17, 2018 • recategorized Mar 9, 2019 by ajaysoni1924 Prince Sindhiya 689 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Hemanth_13 commented Nov 17, 2018 reply Follow Share For I and G LUB is 'I' and it is a lattice per me What is the answer given ? 0 votes 0 votes Deepak Poonia commented Nov 17, 2018 reply Follow Share My doubt is in second hasse diagram for (I,g) lub should be I and j No, $LUB(i,g) = i$ because $i \leq j$ And It's an valid lattice But the Hasse diagram has one extra edge $(g-j)$ which could be removed because it is implied by the Transitivity. 1 votes 1 votes Prince Sindhiya commented Nov 18, 2018 reply Follow Share @deepak bro if it was lattice given directly then they wouldn't give one extra edge (g−j) which is forming transitivity Right ? Here they are asking that which one is lattice that's why we are saying that yeah it is eligible for lattice if we remove that transivity because it is already implied 0 votes 0 votes prabhas44 commented Dec 13, 2019 reply Follow Share i think in fig 1 b and d doesn't have LUB so fig 1 is not a lattice.pls correct if am wrong 0 votes 0 votes Deepak Poonia commented Dec 13, 2019 reply Follow Share i think in fig 1 b and d doesn't have LUB so fig 1 is not a lattice. Correct. 2 votes 2 votes Antaroop commented Jan 25, 2020 reply Follow Share @ Deepakk Poonia In Figure 1, along with (b,d), b and c doesn't have LUB, c and d doesn't have LUB as well.Am I Right ? 0 votes 0 votes Please log in or register to add a comment.