(≤ 720)
what is this?
$f(x) = 3-4x+2x^2$
$f '(x) = -4 + 4x = 0 \implies x=1$
$f ''(x) = 4$
$f ''(1) = 4>0$, therefore at $x=1$ we will get minimum value, which is : $3 - 4(1) + 2(1)^2 = 1.$
Ans for B:
@Dushyant Raut 4
U are correct but as 720 is divisible by 2 it is not included in answer . So including it does not affect ans. But i should not be included.