Given Relation is ABCDE ..now we have some of given FD as
FD={AB→C,DE→C,B→D} ..now we can see that on LHS only 2 attributes are there , which are C and D , so there is no way that we can have A,B,E on LHS .
So every key must have ABE as part of it , so that we can have all attributes in the RHS
So basic minimal set is
ABE ...taking closure of it
(ABE)+=ABCDE
Now prime attributes are A,B,E but as B->D FD is there , a part of key is determining the nonkey , which is voilation of 2NF
so given relation is in 1NF only