edited by
1,182 views

1 Answer

4 votes
4 votes

see figure 1 .  it is non interleaving so when we have to read the data of single track , we can read the all track in single rotation 

see figure 2    it is single interleaving so when we have to read the data of single track, we can read all data of single track  in 2 round 

because 

in single interleaved disk the sectors are not arranged sequentially like 0,1,2,3...7. They are separated by 1 interleaved sectors. 

means

when we read 0 sector  after we have to pass through 4 to read sector 1 and to read sector 2 we have to pass through 5 

so

to read total data (one track data) it will take 2 rotation

see figure 3    it is double interleaving so when we have to read the data of single track, we can read all data of single track  in 2.75 round 

hint watch the 7 in the figure means when we read all the 8 sector we have to cover 2 full rotation + 3/4 rotation 

now come to question 

300 rpm  => 300 rotations --> 60 secs

                        1 rotation --> 0.2 secs

and  time for arm for correct it at position  0 sector is =1/2 of  full rotation =0.1 s

.so total time to read all data =time to set arm + time to read data

                                              = 0.1 s+2.75 * 0.2 s

                                              =0.65 second

                                             =650 ms

edited by

Related questions

0 votes
0 votes
2 answers
1
0 votes
0 votes
1 answer
2
chirudeepnamini asked Jan 28, 2019
466 views
Consider a disk containing 10 equidistance tracks, the inner track capacity is 20 MB and diameter is 1 cm;
0 votes
0 votes
1 answer
3
0 votes
0 votes
0 answers
4