Gateforum Test Series: Programming & DS - Programming In C

Question

What will be the output of the following program

[Addresses of the variables are assigned continuous]

#include<stdio.h>

void main()

{

int a = 4, b = 8, c = 12, d, e, f ;

int *x=&a , *y=&b, *z =&c ;

d =x - y ;

e =y - z ;

f = d - e ;

printf("%d" ; f) ;

}

(A)Compiler error

(B) -8;

(C)8;

(D) 2;

Comments

it may help you http://www.c4learn.com/c-programming/c-subtracting-pointers/

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0 ???

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I am getting 0 as the answer and I feel that's the correct answer as well.

Answer 1

Options are incorrect as the answer is 0.

Let's say address of 'a' = 104;

address of 'b' = 108

address of 'c' = 112

address of 'd' = 116

address of 'e' = 120

address of 'f' = 124

x, y, and z are pointer variables. Therefore, they will store the address of the variables 'a', 'b' and 'c'.

So,

d = x - y = 104 - 108 = -4 / 4 = -1 (Divided by the size of integer)

e = y - z = 108 - 112 = -4 / 4 = -1 (Divided by the size of integer)

f = -1 - (-1) = 0

Now, printf statement will print the answer = 0.

Comments

@mahub

The answer given by them is wrong !

Even options too wrong.

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@`JEET

you have to edit your answer, it is your responsibility, otherwise some of the aspirants may mis-lead by your answer !

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@`Shaik Masthan Ok I will edit it now.