#c book

Question

#include<stdio.h>

int main()

{

int num=10;

do

{

while(num++ <10);

}while(num++ <=11);

printf(“%d”,num);

}

Comments

14

=============

do

{

while(num++ <10);   //pass1 10<10 false   pass2 12<10
printf("%d",num);  //pass1 num=11 //pass2 num=13
}while(num++ <=11);   //11<=11 true go again in do while and post increment num  PASS2 : 13<=11 false and post increment num = 14

printf("%d",num);

---

Output = 14

The key point in this question is: No matter what the do while loop will execute at least once.

After 1st while loop "while(num++ < 10)", num = 10.

After second while loop, "while(num++ <= 11), num = 12. //True.

Will go to do again, after the first while loop.

num = 13, after second while loop num = 14.

//Even though the condition is false but since ++ operator is used before the condition check, therefore it will implement post-increment and the value will be incremented to one everytime.

Answer 1

The output of this code should be 14.

The key point in this question is: No matter what the do while loop will execute at least once.

After 1st while loop "while(num++ < 10)", num = 11.

After second while loop, "while(num++ <= 11), num = 12. //True.

Will go to do again, after the first while loop.

num = 13, after second while loop num = 14.

//Even though the condition is false but since ++ operator is used before the condition check, therefore it will //implement post-increment and the value will be incremented to one everytime.