0 votes 0 votes Lone Wolf asked Nov 21, 2018 • edited Nov 21, 2018 by Lone Wolf Lone Wolf 640 views answer comment Share Follow See all 11 Comments See all 11 11 Comments reply Show 8 previous comments Lakshman Bhaiya commented Nov 21, 2018 reply Follow Share $(2-2)!=0!=1$ where you got $(-ve)!?$ 0 votes 0 votes kumar.dilip commented Nov 21, 2018 reply Follow Share @Lakshman Patel RJIT Earlier was x = 0 Not x = 2. 0 votes 0 votes Lakshman Bhaiya commented Nov 21, 2018 reply Follow Share oh, now $x=2$ $e^{x}=1+x+\frac{x^{2}}{2!}+\frac{x^{3}}{3!}+.......+\frac{x^{r}}{r!}+..........(for$ $all$ $x)$ 0 votes 0 votes Please log in or register to add a comment.
