0 votes 0 votes the total number of logic hazards circuit could contain and the no. of product terms needed to eliminate these hazards respectively are __________________?? am getting 1,1 Gate Fever asked Nov 23, 2018 • edited Nov 23, 2018 by Gate Fever Gate Fever 614 views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply Show 7 previous comments Gate Fever commented Nov 23, 2018 reply Follow Share given answer is 3,3 0 votes 0 votes Hemanth_13 commented Nov 23, 2018 reply Follow Share Shaik Masthan written beside the image A`B`D` + AD + ABC` + AB`C 0 votes 0 votes Shaik Masthan commented Nov 23, 2018 reply Follow Share F = B' . D' + A B C' + A. C. D = ∑m(0,2,8,10,11,12,13,15) = B' . D' + A B C' + A. C. D + A C' D' + A B D + A B' C ∴ therefore there are 3 terms which are Redundant Prime Implicants ===> these 3 terms are needed, to eliminate the Hazards. 0 votes 0 votes Please log in or register to add a comment.
