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In IEEE 754 single precision, according to the given format:

  • sign bit= 1 (the number is negative)
  • exponent=$(10111101)_2=(189)_{10}$
  • Mantissa=$100100...000$

So $V_E=(-1)^s*1.M*2^{E_B-127}$

$V_e=(-1)^1*1.10010*2^{189-127}$

$V_E=(-1)*(1.5625)_{10}*2^{12}*2^{50}$

$V_E=-6400*2^{50}$

So the $P=-6400$

Ref: Floating point

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