self doubt programming

Question

unsigned int i=1;

int j=-4;

printf(“%u”,i+j);

what is printed by following program fragments?

answer is given as “an integer that changes from machine to machine”.

Comments

I think Integers are stored in 2's complement form so convert -4 to 32 bit 2's complement but if the same number is interpreted as unsigned then sign will be positive and just the magnitude will be considered and sign bit is MSB for the unsigned number.

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i think integer size in various computers computers different thats why

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That's because int size may vary. But generally int size is 4B. So for this you will get some big value. And not -3.

 

But had it been

printf("%d", i+j);

Then you would get -3.