if every instruction take 1 cycle and there are no conflict then total cycles taken will be
1*5+(200-1)*1 = 204 cycles
since operations takes different cycles then the stalls will be
for ADD 1 cycles ---- stalls = 0
for MUL 3 cycles ---- stalls = 2
for DIV 5 cycles ----stalls = 4
total stalls suffered = 100*0 + 25*4+ 75*2= 250
total no of cycles required for execution of 200 instruction= 204+250 = 454 cycles.
see reference: https://gateoverflow.in/204125/gate2018-50
let me know if there is any mistake in the solution provided.
