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1 votes
1 votes
Decompose below relation into 2NF,3NF and BCNF with lossless join and Dependency Preserving.

$R(ABCDE)$

$F=\{AB\rightarrow C,DE \rightarrow C,B \rightarrow D\}$

 

According to my analysis

The only key here is $ABE$

So, Dependencies $AB\rightarrow C,B\rightarrow D$ are partial dependencies.

I decomposed as below

$R_1(ABC) \{AB\rightarrow C\}$

$R_2(BD)\{B \rightarrow D\}$

$R_3(CDE) \{DE \rightarrow C\}$

And All three above are in BCNF as well.

Is my decomposition correct?

1 Answer

0 votes
0 votes
It is Lossy Decomposition. Dependency preserving decomposition is not possible till BCNF.

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