28 views
The number of binary matrices of order  $N*N$  whose determinant is exactly zero.
0
0

yeah i checked that but i didn't find any method or may be i overlooked it.

+1

let Y(n) be number of binary matrices of order  $N \times N$  whose determinant is exactly zero.

$Y(n) =$$\large 2^{(n^2)} - n! * \binom{2^n -1}{n} + n! * X(n)$

I don't think it is required to to remember all these things for GATE.

0

actually i thought it also have some trivial method as odd/even #determinant matrices has but someone on SO mentioned it as somehow tough job so yeah may be it wont be asked.

+1 vote
1
2