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In a connected simple graph with 30 edges the maximum number of vertices possible are

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As the graph is a simple connected graph , for a simple connected graph with n vertices minimum no of edges is n-1.

So n-1=30 implies n=31
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A graph with n vertices has $\frac{n\left ( n-1 \right )}{2}$ edges

$\therefore \frac{n(n-1)}{2} = 30$

n(n-1) = 60

n2-n=60

n2-n-60=0

Applying Sridharacharya formula, we get n = 8 (approx)

Eliminating one of the roots as vertices cannot be negative.
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