1 votes 1 votes consider the private key cryptosystem has 3 keys,3 plain texts and 4 cipher texts K={k1,k2,k3} M={m1,m2,m3} C={c1,c2,c3,c4} Gate Fever asked Nov 30, 2018 Gate Fever 415 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments srestha commented Nov 30, 2018 reply Follow Share why B) correct for 32? That means 3 keys are required for one plain text to one cipher text? 0 votes 0 votes Gate Fever commented Nov 30, 2018 reply Follow Share i dont know @srestha mam i thought b is wrong bcoz if i encrypt a msg m1 using k1 then at receivers end it can be decrypted using k2 or k3 as well; which is wrong i thought c is correct bcoz if i get cipher text 1 , then whatever the msg be, it'll always be decrypted using key 1 only; similarly if we get cipher text 2 at receiver side , then for any msg m1,m2,m3 ; it can be decrypted using k2 only!! 0 votes 0 votes Hemanth_13 commented Nov 30, 2018 reply Follow Share @Gate Fever C cannot be the answer because for whatever be the message it (key)its generating same cipher which is wrong Option A could be right because the cipher might be same in some instances Option B could also be correct if all the keys are same:P As the question 31 says "key that maps two different messages to same cipher text" options B fits more as the answer for Question 32 rather than Option A. 0 votes 0 votes Please log in or register to add a comment.