0 votes 0 votes A 40 Mbps broadcast network that controls medium access using polling has 20 hosts and time required for polling the next host is 80 µsec. whenever a node is polled, it is allowed to transmit 4000bytes. Find the efficiency of the broadcast channel 100/9 100/11 80/7 10/11 Computer Networks computer-networks + – Yazanotoom50 asked Dec 1, 2018 Yazanotoom50 2.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Efficiency = Tt/(Tt+Tpoll+Tp) Tt- Transmission time Tp-Propagation time (Can be neglected, because they didn't mention) Tt for 4000Bytes is 4000/5*10^6 s, if we simplify we get 800microsec so Efficiency=800/800+80=10/11 Sanjay Mahaveer answered Dec 1, 2018 Sanjay Mahaveer comment Share Follow See all 0 reply Please log in or register to add a comment.