The given program calculates the factorial of a number x
up to 9, i.e., it calculates 1!
, 2!
, 3!
, ..., (x-1)!
, up to a maximum of 9!
. It then stops when it reaches i=x
or i=10
, whichever comes first.
At the end of the program, the value of j
will be the factorial of (i-1)
or 9
, whichever comes first.
Therefore, the correct answer is (D) (( j = 9!) ∧ (i = 10)) V (( j = (x - 1)!) ∧ (i = x ))
.
Option (A) is incorrect because j
is not necessarily equal to (x-1)!
. It is the factorial of the smaller number between (x-1)
and 9
.
Option (B) is incorrect because the value of j
can never be equal to 9!
since the loop only calculates factorials up to 9.
Option (C) is incorrect because the first part of the OR condition is incorrect, as j
can never be equal to 10!
.