0 votes 0 votes $\Sigma ^{*} - {\left \{ \epsilon \right \}} = \Sigma ^{+} $ $L^{*} - {\left \{ \epsilon \right \}} = L^{+}$ Which of the above is always true ? Theory of Computation made-easy-test-series theory-of-computation regular-expression + – jatin khachane 1 asked Dec 2, 2018 • edited Mar 4, 2019 by akash.dinkar12 jatin khachane 1 722 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply goxul commented Dec 2, 2018 reply Follow Share Should be A, I guess. In B, if $L = {\phi}$, I don't think it holds. 0 votes 0 votes jatin khachane 1 commented Dec 2, 2018 reply Follow Share 2nd inequality is false also for $L = \left \{ \epsilon \right \}$ RIght ?? 0 votes 0 votes goxul commented Dec 2, 2018 reply Follow Share Yes, it is false for that too. 1 votes 1 votes himgta commented Dec 10, 2018 reply Follow Share @goxul how it is not holding for L= phi if L=phi then L*=epsilon L* - {epsilon} is again phi..isin't? 0 votes 0 votes Please log in or register to add a comment.
Best answer 0 votes 0 votes The second one holds true, only If ϵ doesn't belong to L. If a language contains ϵ, then the RHS will always contain ϵ, and LHS won't. Hence second one is false. Lakshay Kakkar answered Dec 3, 2018 • selected Dec 3, 2018 by jatin khachane 1 Lakshay Kakkar comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments srestha commented Dec 3, 2018 reply Follow Share no ,how can it be? 1 votes 1 votes Lakshay Kakkar commented Dec 3, 2018 reply Follow Share @jatin khachane 1 Invalid. 1 votes 1 votes jatin khachane 1 commented Dec 3, 2018 reply Follow Share Thanks and sorry for such silly doubt 0 votes 0 votes Please log in or register to add a comment.