$E_1$ : first card being ace
$E_2$ : last card being ace
Note : $E_1$ and $E_2$ are dependent events (I.e) probability of last card being ace if first card is ace will be lesser than the probability of last card being ace if first card is not ace ....
So, probability of first card being ace = $4/52$
Probability of last card being ace given that first card is ace (I.e) $P(E_2/E_1)$ = $3/51$
$P$($E_1$ AND $E_2$) = $P(E_1).P(E_2/E_1)$ = $4/52 $*$ 3/51$
Correct Answer: $C$