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asked in Computer Networks by Loyal (8.7k points) | 62 views
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I am getting B as an answer
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Propagation Speed :: $200m/μsec$

Bw :: $20Mbps = 20 * 10^6$

Distance :: $20km = 200 * 10 ^ 3m$

propagation delay : $(200 * 10 ^ 3m)/(200*10^6m/sec)$

L=2*Propagationsdelay*Bw

$L = 20,000bits$
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Are u taking The L = Bandwidth * RTT ?

It should be simply L = Bandwidth * Propagation delay becasue here in token ring only one request can happen at a time.
+1
What i did is in 200km it will require 1000micro second

So total capacity is = 20Mbps * 10,000 = 20,000.

Assuming it to be half duplex
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@Na462 I did efficiency = 1

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when we take efficiency = 1 or 100%

then, Length= $T_{p}*BW$

Am I right??

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