The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
0 votes
30 views

 

asked ago in Computer Networks by Loyal (7.4k points) | 30 views
0
I am getting B as an answer
0
Propagation Speed :: $200m/μsec$

Bw :: $20Mbps = 20 * 10^6$

Distance :: $20km = 200 * 10 ^ 3m$

propagation delay : $(200 * 10 ^ 3m)/(200*10^6m/sec)$

L=2*Propagationsdelay*Bw

$L = 20,000bits$
0
Are u taking The L = Bandwidth * RTT ?

It should be simply L = Bandwidth * Propagation delay becasue here in token ring only one request can happen at a time.
0
What i did is in 200km it will require 1000micro second

So total capacity is = 20Mbps * 10,000 = 20,000.

Assuming it to be half duplex
0

@Na462 I did efficiency = 1

Please log in or register to answer this question.

Related questions

0 votes
1 answer
4
0 votes
1 answer
7


Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

43,962 questions
49,517 answers
162,468 comments
65,759 users