4 votes 4 votes Above question modification. This is the actual question Boolean expression$:(x+y)(x+\bar{y})+\overline{{(x\bar{y}+\bar{x})}}$ $(A) x$ $(B)y$ $(C)xy$ $(D)x+y$ Digital Logic digital-logic boolean-algebra 2014-ece + – aditi19 asked Dec 4, 2018 retagged Mar 11, 2019 by Naveen Kumar 3 aditi19 2.4k views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply Na462 commented Sep 29, 2018 reply Follow Share Mine is resolving to ===> x + xy = x because the value of x determines the answer so the answer is x am i correct ? 1 votes 1 votes kumar.dilip commented Dec 4, 2018 reply Follow Share 0 ?? 0 votes 0 votes Bhagyashree Mukherje commented Dec 4, 2018 reply Follow Share Even I am getting 0 0 votes 0 votes aditi19 commented Dec 4, 2018 reply Follow Share answer is x 0 votes 0 votes Lakshman Bhaiya commented Dec 5, 2018 reply Follow Share @aditi19 I'm also getting $0$ How $x$ is possible? 0 votes 0 votes aditi19 commented Dec 5, 2018 reply Follow Share I'm getting 0 too. I dunno why answer is given x 0 votes 0 votes Lakshman Bhaiya commented Dec 5, 2018 i edited by Lakshman Bhaiya Dec 5, 2018 reply Follow Share can you provide me shift name of GATE 2014 ECE? Your question is wrong. I add the question, which is actual question and answer is $x$ Please, when you add the question please type the question using Latex. 0 votes 0 votes aditi19 commented Dec 5, 2018 reply Follow Share oh! probably during copy pasting the sign went missing 0 votes 0 votes Lakshman Bhaiya commented Dec 5, 2018 reply Follow Share $Alwyas$,you can type the question, it will beneficial for others also. thanks 0 votes 0 votes aditi19 commented Dec 5, 2018 reply Follow Share yes 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes $f=(x+y)(x+\bar y)+\overline{(x\bar y+\bar x)}$ $f=(x+x\bar y+xy+y\bar y)+\overline{x\bar y}.\bar{ \bar x}$ $f=(x(1+\bar y+y))+(\bar x+y).x$ $f=x+xy$ $f=x(1+y)=x$ Option (A) is correct. Hira Thakur answered Nov 11, 2022 Hira Thakur comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes while evaluating you get x+xy`+xy+((x`+y).x) =x+xy`+xy+xy =x(1+...)=x Raghav Khajuria answered Sep 29, 2018 Raghav Khajuria comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes $(x+y)(x+\overline{y}) + \overline{x\overline{y} + \overline{x} }$ $xy + x\overline{y} + \overline{x\overline{y}}$ $ (\overline{\overline{x}}) $ $x + (\overline{x} + y)x$ $x + yx$ $x$ Mk Utkarsh answered Sep 29, 2018 Mk Utkarsh comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Answer : A (x+y)(x+y')+(xy'+x')' (x+y)(x+y')+((x'+y)(x)) // (x'+y)(x) = xy x+xy'+xy+xy // x+xy'=x x + xy // x+xy = x x shivam001 answered Dec 18, 2019 shivam001 comment Share Follow See all 0 reply Please log in or register to add a comment.