GATE ECE 2014

Question

Above question modification.

This is the actual question

Boolean expression$:(x+y)(x+\bar{y})+\overline{{(x\bar{y}+\bar{x})}}$

$(A) x$               $(B)y$           $(C)xy$               $(D)x+y$      

Comments

oh! probably during copy pasting the sign went missing

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$Alwyas$,you can type the question, it will beneficial for others also.

thanks

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yes

Answer 1

(x+y)(x+y') = x+xy+xy'=x(1+y+y')=x.1=x

{(x+y')+x'}'= {x+x'+y'}'={1+y'}'=1'=0

(x+y)(x+y') . {(x+y')+x'}' = x.0=0

Answer=0

Answer 2

(x+y)(x+y')+(xy).............after simplification of complement part

now just simplify

x+xy'+xy+0+xy=x ans.