case 1: if in R(a,b) and S(b,c) we have the same values of b then the inner parenthesis evaluates to 0 and then r-0=r(no of tuples in relation r)
case 2: if in R(a,b) and S(b,c) we have no tuple common so the inner bracket gives us r no of tuples and r-r=0
So max=r and min=0