1 votes 1 votes ____ number of underlined graphs can be constructed using $V=(v1,v2, \dots,vn)$. $n^3$ $2^{n(n-1)}/2$ $n-1/2$ $2^{(n-1)}/2$ DS nielit-2018 data-structures graph-theory + – Arjun asked Dec 7, 2018 • recategorized Oct 24, 2020 by Krithiga2101 Arjun 1.1k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply OneZero commented Dec 7, 2018 reply Follow Share B? 0 votes 0 votes Shubhgupta commented Dec 7, 2018 reply Follow Share No of edges present in undirected graph are ${\frac{n(n-1)}{2}}$ so number of graph possibles are $2^{\frac{n(n-1)}{2}}$. 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes Graph with N vertices may have up to $N(N-1)/2$ edges (if loops aren't allowed). Now each edge have only 2 possibilities i.e. either Present or Absent. So overall number of possible graphs is $2^{N(N-1)/2}$ SO OPTION B. Asim Siddiqui 4 answered Feb 17, 2019 Asim Siddiqui 4 comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes → With n vertices no. of possible edges = nC2 → Each subset of these edges will form a graph. → Number of possible undirected graphs is 2(nC2) 2(n(n-1)/2) Answer-B topper98 answered Mar 18, 2020 topper98 comment Share Follow See all 0 reply Please log in or register to add a comment.