2 votes 2 votes $(A+C’)(B’+C’)$ simplifies to $AC’+B’$ $C(A’+B’)$ $BC’+A$ $AB’+C’$ Digital Logic nielit-2018 digital-logic boolean-algebra + – Arjun asked Dec 7, 2018 recategorized Oct 24, 2020 by Krithiga2101 Arjun 842 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes It is based on distributive law which says A+BC=(A+B)(A+C) The question is asking us to implement the law in reverse order,i.e (A+B)(A+C)=A+BC Now,coming to the question, (A+C’) ( B’ + C’) = C’+ AB’ option D s_dr_13 answered Mar 31, 2022 s_dr_13 comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes (A+C')(B'+C') = AB' + AC' + B'C' + C' = AB' + C'(A+B'+1) =AB'+C' $\therefore$ Option D is correct. Satbir answered Feb 15, 2019 Satbir comment Share Follow See all 0 reply Please log in or register to add a comment.