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The general solution of the differential equation $\frac{dy}{dx} = (1+y^2)(e^{-x^2}-2x \tan^{-1} y)$ is:

  1. $e^{x^2} \tan^{-1} y = x+c$
  2. $e^{-x^2} \tan^y = x+c$
  3. $e^x \tan y = x^2+c$
  4. $e^{-x} \tan^{-1} y = x^3+c$
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