1 votes 1 votes The general solution of the differential equation $\frac{dy}{dx} = (1+y^2)(e^{-x^2}-2x \tan^{-1} y)$ is: $e^{x^2} \tan^{-1} y = x+c$ $e^{-x^2} \tan^y = x+c$ $e^x \tan y = x^2+c$ $e^{-x} \tan^{-1} y = x^3+c$ Others nielit-2018 non-gate differential-equation + – Arjun asked Dec 7, 2018 retagged Oct 27, 2020 by Krithiga2101 Arjun 576 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.