1 votes 1 votes If $u=f(y-z, \: \: z-x, \: \: x-y)$, then $\frac{ \partial u}{ \partial x} + \frac{ \partial u}{ \partial y} + \frac{ \partial u}{ \partial z} $ is equal to: $x+y+z$ $1+x+y+z$ $1$ $0$ Others nielit-2018 non-gate differentiation partial-order + – Arjun asked Dec 7, 2018 retagged Oct 27, 2020 by Krithiga2101 Arjun 648 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.