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1 vote
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If $2a+3b+c=0$, then at least one root of the equation $ax^2+bx+c=0$, lies in the interval:

  1. $(0,1)$
  2. $(1,2)$
  3. $(2,3)$
  4. $(1,3)$
in Quantitative Aptitude
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3 Answers

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Here we can see that X can take values as 3 or +√2 or -√2

Since it's given as positive interval the values of root can be lie in between 1.414 to 3 so (1,3)

So option D.
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According to official answer keys the answer is A

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 least one root of the equation ax2+bx+c=0ax2+bx+c=0, lies in the interval:(0,1)

option-A

ago 1 flag:
✌ Duplicate (Kanwae Kan)
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