# NIELIT 2018-17

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If $2a+3b+c=0$, then at least one root of the equation $ax^2+bx+c=0$, lies in the interval:

1. $(0,1)$
2. $(1,2)$
3. $(2,3)$
4. $(1,3)$

retagged

Here we can see that X can take values as 3 or +√2 or -√2

Since it's given as positive interval the values of root can be lie in between 1.414 to 3 so (1,3)

So option D.

least one root of the equation ax2+bx+c=0ax2+bx+c=0, lies in the interval:(0,1)

option-A

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✌ Duplicate (Kanwae Kan)

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