1 votes 1 votes The value of $\int_c \frac{2x^2-5}{(x+2)^2 (x^2+4)x^2}dx$, (where $c$ is the square with vertices $1+i, 2+i, 2+2i, i+2i$) is: $0$ $\pi i$ $2 \pi i$ $4 \pi i$ Others nielit-2018 non-gate integration + – Arjun asked Dec 7, 2018 • retagged Oct 27, 2020 by Krithiga2101 Arjun 650 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.