4 votes 4 votes Divide $88$ into four parts such as first part known as $a,$ second part $b,$ third part $c,$ and fourth part is $d,$ when $5$ is added to the first part, $5$ is subtracted from the second part, $3$ is multiplied by the third part and the fourth part is divided by $5,$ then all results value are equal. Find the value of $a, b, c$ and $d$ respectively. $7, 17, 4, 60$ $8, 25, 5, 50$ $10, 30, 3, 45$ $17, 7, 4, 60$ Quantitative Aptitude nielit-2018 quantitative-aptitude number-system + – Arjun asked Dec 7, 2018 retagged Oct 23, 2020 by Krithiga2101 Arjun 3.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes a+b+c+d=88 a+5=b-5=3*c=d/5 a+5=3c => a=3c-5 b-5=3c => b=3c+5 d/5=3c => d=15c a+b+c+d=88 => 3c-5 + 3c+5 + c + 15c = 88 => 22c = 88 => c=4 a=3c-5 = 3*4-5 = 7 b=3c+5 = 3*4+5 = 17 d=15c = 15*4 = 60 (a,b,c,d) = (7,17,4,60) Hence, Option A is the answer Balaji Jegan answered Dec 7, 2018 Balaji Jegan comment Share Follow See 1 comment See all 1 1 comment reply Danishgupta commented Sep 17, 2020 reply Follow Share Great explanation balaji 1 votes 1 votes Please log in or register to add a comment.
0 votes 0 votes Can be done by option elimination, It is given that a+5=b-5 now check option (A) 7+5=17-5 no other option follow this. Correct answer is A Peeyush Pandey answered Dec 7, 2018 Peeyush Pandey comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes a+b+c+d=88--------1 a+5=b-5=3c=d/5=K Find value of a,b,c,d in term of K a=K-5 b=K+5 c=K/3 d=5K Put a,b,c,d in eq1 and you will get K=12 a=K-5=12-5=7 Similarly b=17,c=4,d=60 So ans is A himanshu26 answered Mar 22, 2020 himanshu26 comment Share Follow See all 0 reply Please log in or register to add a comment.