Given-
- Bandwidth = 150 Mbps
- Propagation delay (Tp) = 6x10^4 micro sec = 60ms
- Frame size = 5000 bytes
- Go back N is used where N = 100
Transmission delay (Tt)
= Frame size / Bandwidth
= 5000 bytes / 150Mbps
= (5000 x 8 bits) / (150 x 10^6 bits per sec)
= 2.66 x 10^-4 sec
= 0.266 msec
a = Tp / Tt
a = 60 msec / 0.266 msec
a = 225.5639
Efficiency (η)
= N / (1+2a)
= 100 / (1 + 2 x 225.5639)
= 100 / 452.1278
= 0.2211
= 22.11 %
Maximum data rate possible or Throughput
= Efficiency x Bandwidth
=0.2211 x 150Mbps
= 33.1764 Mbps
≅ 33.18 Mbps ANSWER