in Probability
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1 vote
1 vote

A group consists of equal no of men and women .of this grp 20% of men and 50% of women are unemployed .If a person is selected at random from this group ,the probability of the selected person being employed is ____________

For this I did 

P(E)=P(M∩ E) +P(W∩ E) where U and E are for employed and unemployed ,Now P(M)=P(W)=1/2 

Now P(E/M)= 0.8    and P(E/W)=0.5 

so we get 

P(E)= 1/2 * 0.8 +1/2*0.5 =13/10 

where is the mistake , answer given is 65% .

in Probability
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1 Answer

2 votes
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P(employed)=1-P(not employed)

P(not employed)=0.5*0.5+0.5*0.2=0.35

Therefore probability of selecting employed person=1-0.35=0.65

2 Comments

what is wrong in my approach ?
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It is correct- you calculated sum wrong.
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