pda doubt closed

Question

Consider the following PDA:

The language accepted by the given PDA is:

 

1. L = {(b^n a b^n a )^m | m, n >= 0}

 

2. L = {b^n a b^n a | n >= 0} {bn | n >= 0}

 

100. L = {b^n a b^n a | n >= 0}

 

500. L = {(b^n a b^n a )^m | m, n >= 0} {bn | n >= 0}

Comments

there is no transaction with (q0, a, z0), if we put n=0 in all options then there will be aa only and that time top of stack will be z0.

So, transaction from initial state with (a ,z0) should be there

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@Devwritt

yes correct .what  if , we put a,zo/zo for qo  ?

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