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A - B

B - C

C - A

  

 

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Minimal Set may not be unique always.

Consider this R(ABC) with FD:{ A→ B,B→ C,C→ A, B→ A, C→ B, A→ C}

By solving we can get 2 minimal sets

M1: A→ B, B→ C. C→ A

M2: B→ A, C→ B, A→ C

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