MadeEasy Subject Test 2019: Programming & DS - Programming In C

Question

char *a = “MADEEASY”;

char *b = “GATECSIT2019”;

char *r = a;

char *s = b;

printf(“%d”, (int) strlen (b+3[r] – 1[s]));

return 0;

 

Whats the output? Answer given 8

Answer 1

b+3[r]-1[s]

= &b[0] + r[3] - s[1]

=&b[0] + 'E' - 'A'

=&b[0] + 4

=&b[4]

="CSIT2009"

strlen("CSIT2009") = 8

Answer 2

3[r] means r+3 and 1[s] means s+1 so r+3 will be D  ans s+1 will be A so subtracting it we get value as 3

now b+3 is means string length after E which is CSIT2019 which is of length 8