1 votes 1 votes Balaji Jegan asked Dec 11, 2018 Balaji Jegan 466 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Lakshman Bhaiya commented Dec 12, 2018 i edited by Lakshman Bhaiya Dec 13, 2018 reply Follow Share Algebraic Multiplicity$(AM):-$ Let $A=[a_{ij}]_{n\times n}$ be a square matrix of order $n$ whose characteristics equation $|A-\lambda I|=0$ The multiplicity of an Eigenvalue is called algebraic multiplicity of that eigenvalue. Geometric multiplicity$(GM):-$ Geometric multiplicity define as $GM=n-r(A)$ Where $r(A)=$rank of $A$ that $\lambda$specific $r(A)=[A-\lambda I]_{n\times n}$ and $n=$order of the matrix $\Rightarrow$ If $AM=GM$ then the matrix is diagonalizable. 0 votes 0 votes Shubhanshu commented Dec 12, 2018 reply Follow Share What is the final answer? 0 votes 0 votes Lakshman Bhaiya commented Dec 12, 2018 reply Follow Share @Shubhanshu After that, i'm not able to solve, but i can try. 0 votes 0 votes Please log in or register to add a comment.