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Unix I-node has block size 8 KB and file possible with triple indirect is 128 GB.Number of bits disk block address contain is?
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See here triple indirect is given,

For triple indirect max possible file size is

= {(block size) /DBA}^3 * Block size

// DBA:Disk Block Address

So, 128 GB= (8 KB/DBA) ^3 *8KB

(DBA)^3 = 2^15 B

Cube root both side, and you will get

DBA =32 Bytes = 32*8 bits=256 bits

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