Register

#discrete matmatics

• edited by
484 views

2 Answers

0 votes
0 votes

Solution:

$a_n = \frac{1+\frac{2}{3}(2^{2n}-1)}{2^n}, n \geq 0$

User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

2 votes
2 votes
1 answer
1
Jatin18 asked Jun 11, 2017
1,351 views
#Discrete #Combinatorics
The number of ways in which n distinct objects can be put into two identical boxes so that no box remains empty, is a) 2^n - 1 b) 2^n - 2 c) 2^(n-1) - 1 d) None of these Please explain your answer.
The number of ways in which n distinct objects can be put into two identical boxes so that no box remains empty, isa) 2^n - 1b) 2^n - 2c) 2^(n-1) - 1d) None of thesePleas...
User Avatar
Link Copied!