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If the broadcast address of the subnet is given as 163.93.63.255, which of the following mask cannot suit the above address?

A) 255.255.240.0

B) 255.255.248.0

C) 255.255.128.0

D) Both (a) and (b)

1 Answer

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Given: broadcast address of the subnet is given as 163.93.63.255

given address's class is class B (range is 128 to 191 in decimal) and default mask for class B is: 255.255.0.0

Now, in given question, last 2 octet 63.255 will 0 0 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . Here, in 3rd octet(63) 2 bits are 0 so at least 2 bits from 3rd octet belongs to subnet bits(it can be more than 2).

Now, 192= 1 1 0 0 0 0 0 0

subnet mask value will be(at least) 255.255.192.0 and/or it can be 255.255.224.0 and/or 255.255.240.0 ....and so on

 

So, C) 255.255.128.0 is not a possible subnet mask

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