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Can someone solve this and tell how it’s 160.

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1_ _ _ _ _ _ _   --> 7 blanks can be filled in $2^7$

_ _ _ _ _ _ 0 0 --> 6 blanks can be filled in $2^6$

1_ _ _ _ _0 0  --> 5 blanks can be filled in $2^5$

n(AUB)=n(A)+n(B)-n(A n B)

            = $2^7$ +  $2^6$ - $2^5$

            =  $2^5$( $2^2$+ $2^1$-1)

            = 32* (4+2-1)

            = 32*5 ==> 160
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