$\large X : \left ( P \vee Q \right ) \rightarrow R$
$Y : (P \rightarrow R) \vee (Q \rightarrow R)$
$Y : (\overline{P} \vee R) \vee (\overline{Q} \vee R)$
$Y : (\overline{P} \vee \overline{Q} \vee R)$
$Y : (\overline{P \wedge Q}) \vee R$
$\large Y : (P \wedge Q) \rightarrow R$
now Y can be false if and only if $P$ and $Q$ are true but $R$ is false but in such case $X$ is also false
From this we can conclude that there exist no case where $X \rightarrow Y$ results in False.
$X \rightarrow Y$ is a tautology