answer will be 49
given Each such allocation takes 1 nano second
first set of 3 instruction take 13 ns ,How?
1 ns for allocation ,3 ns for GF, 1 ns for Uf allocation , 8 ns for UF =13 ns
after that every set of 3 instruction take 9 ns (3 times same thing happen)
last one take 9 ns
so total 13+9+9+9+9=49 ns