Binomial distribution

Question

Is there any relation between MEAN, VARIANCE and MODE for binomial distribution?

Let, Mean = 8, variance = 6 for any binomial distribution.

np = 8 and npq = 6 => q=$3/4$, p=$1/4$

Now is there any relation to find value of MODE ?

Comments

see this https://math.stackexchange.com/questions/117926/finding-mode-in-binomial-distribution

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@Lakshman Patel RJIT

Not able to understand why they have taken the ratio of $^nC_{k+1}$/$^nC_{k}$ at all

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i don't think so

In bionomial distribution only 3 formula that I know and also  given in all standard books that's

Mean = np

Variance = npq

mean deviation = sqrt(npq)

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@Magma

answer given is :

Mean - q < Mode < mean + p

8-3/4 < mode <8+1/4

since mode should be an integer value,

mode = 8

link shared by @Lakshman Patel RJIT has explained the concept, but I am unable to understand that, please help !