1 votes 1 votes An $\epsilon$ free LL(1) grammar is also a SLR(1) and hence LALR(1) and LR(1) too. Is this statement true ? Compiler Design compiler-design parsing grammar + – junaid ahmad asked Dec 20, 2018 junaid ahmad 627 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Hemanth_13 commented Dec 20, 2018 reply Follow Share I don't think this statement is true 0 votes 0 votes kumar.dilip commented Dec 20, 2018 reply Follow Share I think the statement is True. See the discussion here. https://gateoverflow.in/945/gate2003-57?show=276990 1 votes 1 votes sushmita commented Jan 7, 2019 reply Follow Share yes it is true 1 votes 1 votes Please log in or register to add a comment.