1 votes 1 votes Set Theory & Algebra discrete-mathematics group-theory zeal zeal2019 + – Prince Sindhiya asked Dec 21, 2018 retagged Nov 29, 2023 by Hira Thakur Prince Sindhiya 479 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Prince Sindhiya commented Dec 21, 2018 reply Follow Share how you got 4th 0 votes 0 votes Satbir commented Dec 21, 2018 reply Follow Share Option 1 is correct coz it follows closure, identity is 1, invere of every element exist and multiplication follows associativity. Option 2 is also correct coz it follows closure, identity is 0, each element has inverse and associativity is applicable on addition. Option 3 does not follows associativity. Option 4 is a cyclic group i think....every cyclic group is abelian group and thus it is also a group. 0 votes 0 votes Prince Sindhiya commented Dec 21, 2018 reply Follow Share 2) closer not satisfy 1+1=2 which is not in set 0 votes 0 votes Please log in or register to add a comment.