in Set Theory & Algebra edited by
288 views
1 vote
1 vote

 

in Set Theory & Algebra edited by
288 views

4 Comments

how you got 4th
0
0
Option 1 is correct coz it follows closure, identity is 1, invere of every element exist and multiplication follows associativity.

Option 2 is also correct coz it follows closure, identity is 0, each element has inverse and associativity is applicable on addition.

Option 3 does not follows associativity.

Option 4 is a cyclic group i think....every cyclic group is abelian group and thus it is also a group.
0
0
2) closer not satisfy 1+1=2 which is not in set
0
0

Please log in or register to answer this question.