0 votes 0 votes Consider the following cache A and B .let the average access times in cache A and B is $t_A$ and $t_B$ respectively.the value of $t_A+t_B$ _(in ns) Answer is given as 30.18 ns I am getting 31.2 ns .Please verify it . CO and Architecture co-and-architecture cache-memory made-easy-test-series + – Prateek Raghuvanshi asked Dec 22, 2018 edited Mar 4, 2019 by ajaysoni1924 Prateek Raghuvanshi 958 views answer comment Share Follow See all 16 Comments See all 16 16 Comments reply Show 13 previous comments Deepanshu commented Jan 6, 2019 reply Follow Share 15% miss rate not hit rate u r taking it as hit rate 2 votes 2 votes Nandkishor3939 commented Jan 6, 2019 reply Follow Share omg !! Thank you now the answer is correct :) one last question... if nothing is mentioned in the question then are we supposed to take hierarchical cache memory?? @Deepanshu @MiNiPanda 0 votes 0 votes MiNiPanda commented Jan 6, 2019 reply Follow Share @Nandkishor3939 yes . 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes By default memory access in cache is hierarchical. For A EMAT = $5 + 0.2 * 80 = 21 ns$ For B EMAT = $3 + 0.4( 6 + 0.15*80) = 10.2 ns$ So sum = $31.2ns$ smsubham answered Mar 23, 2020 smsubham comment Share Follow See all 0 reply Please log in or register to add a comment.